Java get parent directory from string path length-2]); get all the sub parent folders from given The java. For example: Input: Users/Documents/SVG Output: Documents/SVG Java 7 introduced java. println(directories[directories. lastIndexOf() to retrieve just the immediate parent directory. getRealPath() isn't the answer, but:. I need to parse a file path to get the filename from it. My main Program is in the Main folder(e:\ProjectFile\Main) . Paths; The java. How to get the parent directory of a file? Solution. mp3 I want to get the name of the Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Is there a way to get the path of main class of the running java program. It uses Files. Since Oracle convoluted the notion of when a In Matlab, I have a string containing a path to a file: path = 'C:/Data/Matlab/Dir/file. FilenameUtils. io. My requirement is to create folder at provided path and i want to add validation that that folder How do we actually discard last file from java string and just get the file path directory? Random Path input by user: C:/my folder/tree/apple. png” but I do not know it’s file directory, There is a tutorial for copying files using java. dir" Finally, here's an approach that might be more helpful for your end application. So the question is how do you know the path where the Java Downvotes because System. I think there is a way it may help you if and only if the file is in the program directory. " to go up the directory structure in arbitrarily complex ways. Path getParent() Method Overview. getParent(). separator); I need the array to check if certain folders are at the right I need to get real path for file in my WebContent directory, so that framework that I use can access that file. Consider the following path: /bin/src/config/file , I would like to get /bin/src/config in Java. split(File. txt and I also have a map of childeId-parentId. getAbsolutePath(); Then create a file object from Rather than keeping everything string-based, you should use a class which is designed to represent a file system path. So I created one myself: public static string ExtractFolderFromPath(string fileName, string Step 1 : Create a file with path as . normalize() from commons IO, but I can't seem to be able to get a resource in another folder to get a Java FXML file. I don't know what 'with respect to the web application we are using' means if getServletContext(). The Still, I'm wondering if there is some nice way, which works universally, for getting the path to the directory where a given . getParentFile(): This is the most straightforward way if your file has a parent directory. apache. Consider the following path: /bin/src/config/file, Given a path like /a/. Mark's comment is a better solution than lastIndexOf(): These Use the getParentFile() method of the File object to obtain the parent directory as another File object (parentDirectory). class file with This code checks for the existence of the directory first and creates it if not, and creates the file afterwards. Use the getParentFile() method to get the parent directory of the file. Parents can have n number of children but children have one immediate parent. I have the need to specify paths to directories to a Java program and would like to specify them as a URI rather than just a String directory path. dirname() function simply returns the parent directory as the output while taking the current directory as the input by passing it as an One of my file and the current path is in. getFilesDir(). How to I'm looking for a way to get all the names of directories in a given directory, but not files. I'm trying to get the parent full path of parent directory in a path. dir"); If you want to get Edit: The normalization covered in this answer only happens when the path is used to access the file system, but not on the string itself. e. File is that it can normalize paths to a predictable format. file. getSelectedFile(); String fullPath = file. I want to get the path to each child from parent in Java. I Guessing that what you want to do, is call Files. – BullyWiiPlaza Commented Sep 29, 2017 at 0:13 The typical __dirname solution doesn't work in an ESM scope. String PROJECT_ROOT_PATH = System. getProperty("user. /stuff/xyz. '/home/foo/bar. It has the same output as the previous, but lends itself to an inversion of control where you can I am trying to use a relative path to locate an executable file within a Java class instead of hard-coded lines which worked, but using something like: final static String directory Consider using org. split() Yes, Path copes with the platform dependent problem of slash/backslash, but only if the file path is from the same machine (or platform). To move one level higher in the directory tree, I came up with the following solution: import { fileURLToPath } from "url"; import Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Surprisingly there is no simple, yet functional solution. System. split("/"); System. Following example shows how to get the parent directory of a file by the use of file. getParentFile() I don't know what the return in terms of being absolute or relative, but if it's absolute you can always find Introduction. If you are sure that java. home is set accurately in all For example i have the path : C:\Users\Alexander\Desktop\Hello\Hello2\AudioFile. test and MyClass inside this package. D:/ |---Project |-----bin |-----src I want to get the path as D:\Project\bin\. split() If the files don't exist, you could use the String. Use File 's getParentFile() method and String. If the given Path is a folder, I’m writing a java program that needs to find a file directory only having the file name. split first string in list with delimiter "/". An alternative is to set Java 7 made this type of thing easy with lots of flexibility. DirectoryInfo? Version for a directory. dir"); does not always return an OS drive path, rather the application's directory. To illustrate the issue please Get the directory from a file path in java (android) get the path of file in android (In general, String path = context. The parent path of this path object In this program, we will demonstrate how to retrieve the parent directory of a file using the File class in Java. The Java File getParent() method returns the pathname string if this abstract path name's parent or null if this pathname does not name a parent directory. getCanonicalPath() then : if file is inside a specific To obtain the File for a given Class, there are two steps:. For every splitted string you split the string using "/". You can extract the base path, file name, extensions etc with any flavor of file separator: String url = Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, This function returns the Parent of the given file object. Therefore I wrote three methods, which all use a I have a Business folder(e:\Business) in this folder I have compiled file . String File. So, if your The following line will locate you to the base directory, where are the src, resources and target folders located:. Transform toAbsolutePath() if it is / means an absolute path, save Java web-apps where / means relative to context. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about I don't know of library function to do this in one step. And am not able to accomplish this using Files. ), giving a/b/d. It works with java se 7+. out. I think you have misunderstood the use of class. get-item is your friendly helping hand here. static boolean isChildPath(Path parent, Path child){ Path pn = Problem Description. In fact it's a bad habit to get into because class loader resources are not java. dir"); File file = new File(PROJECT_ROOT_PATH ); Step 2 : Check It does not use 3rd party library, instead it uses NIO2 of Java 7. new File("/", inputPath). Here is one using java. One way would be to use the system property System. I'm not trying to break above the base directory I get with getResource("/"). txt Let's say I have a file in major folder say lump. Since it seems like he was looking for a way to do this from within a script (find the script's current directory and it's parent and do something relative to where the script lives) I'm trying to implement a function that given any JSONObject and a path String, would return the object's attribute corresponding to the path. You can use the file: prefix in the @PropertySource annotation instead of classpath:. Retrieving the parent directory of a file is a common task in file management. My directory structure is starts from the current application directory, Means in current projects I have many strings like this D:\just\a\path, the string might differ in number of elements, maybe C:\just\another\longer\path. path. txt"). /d, I would like to remove all the "current directory" indicators (i. Below programs will illustrate the use of the getParent() function: Example 1: We How to get the parent directory of a file? Solution. Java provides several ways to accomplish this using both the java. Could someone tell me how to get the parent directory of a path in Python in a cross platform way. The Path class represents a file path in the Java File System, which can denote a directory or a file. walkFileTree method, which might Description. This path may and will use ". lines() on a resource that comes from the classpath - possibly from within a jar. The function returns a string object which contains the Parent of the given file object. class file is located? I guess you could get it from the I had performance doubts using the Java URL class for just extracting the path from an URL and thought that this is an overkill. Get list of paths in List pathList. Declaration. txt to reference the file, as this is the @GianCarlo: You can try calling System property user. structure is. 2. specifier. One way to do You don't need to mess with class loaders. ; it does not operate at the OS If the Files actually exist on the box, you could wrap the Strings up in a File object and call File. dir"); System. E. file包中,因此Java Path接口的标准名称是java. You need to change below line . getParent() and Where File is the parent directory ("C:\Users\sd\Desktop\sdsd) Now the code above works file and list me all the files in the that directory and sub directory, like. The resource I'm trying to read is relative to another path, but still inside the jar and something that An advice of limited use, as it relies on the working directory to be the maven root. normalize() simply removes redundant pieces of strings in your path, like . getPath() always returns a string with relative I want to have a new string which contains the path to the "project" folder, from similar strings like above example, something like. 1. Please note that I couldn't verify some of your method calls as I So, I need to make sure if a specified file has a parent directory. println(fullPath); Lets create class Folder. (get-item $scriptPath ). First split the string using ",". means same folder as the currently running context means the parent folder of the currently running context. dat Is there any way to get valid/existing parent from provided path without looping. It's working directory of the process. . When the user clicks the text field an event is triggered and the JFileChooser is launched. To reliably get a file from the resources in Spring Boot application: Find a way to pass abstract resource, for example, InputStream, URL instead of File Use framework facilities to get the resource CLASSPATH , as the name suggests it is the path to class. File objects when they are in a jar archive. The name of the parent directory of the file or directory can be obtained using the Not perfect? This is actually the most reliable since the other proposed suggestions returns the current working directory which is not per se the folder where the JAR is located. m' I want now want to extract the 'Dir' part of the string. Basically my problem is with the path, because I know that listing files under a directory The relative path works in Java using the . Path; import java. It only takes String file as attribute, so I need to get the real path to this file in I have a small java GUI application with a text field on it. I need to construct a string representation of an URI from FilePath(String) on windows. get() method in Java simplifies cross-platform file management by converting strings or URIs into file paths. (ie: the directory you were in when you started the JVM) You can load files from the same directory * as the . or . String FileName = I need to get the paths of files and their parent directories in java from a given directory but not including it. I tried using It worked for me. Inside your ressources folder (java/main/resources) of your jar add your file (we assume that you have added an xml file Correct solution with "File" class to get the directory - the "path" of the file: String path = new File("C:\\Temp\\your directory\\yourfile. /var/data/stuff/xyz. String. I want to get the last element path. getParent(); which will return: Quit Example: file:///path/to/files. C:\Program Files ---> C:\ and C:\ ---> C:\ If the directory doesn't have a parent you I have the following problem in a Java application By this statment I retrieve the current location of my application: URL location = String currentpath = System. println("current dir = " + currentpath); It displays my current path- current dir = C:\\Users\\TKMAHQB Better use a package, and give the classpath till the directory containing your package. That way you will be able to give different namespaces to your classes. Create an Object Node which contains a parent (Node) and a List of children (Node). File class Using File. Definition: The getParent() I've tried numerous methods now, including FilenameUtils. var newPath = As Jarrod Roberson states in his answer here:. getResource. zip' * @return a list containing all root folders This code will return the folder path where I issued the java -jar command. import java. Is there any Although, if getting the directory path from a string is the only functionality you need, then Boost might be a bit overkill (especially since Boost::Filesystem is one of the few Fantastic answer. getAbsolutePath first, so it also works with relative paths. Utilizing String. txt"); String path = This will print "System32", and if the directory does not exist it returns an empty String "". Path=Other Path=Or Path=Folder with spaces Path=Some Root=c:\ You probably want to use f. parent Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about The current directory is not (necessarily) the directory the . You can use the getParent() method of Path in java. String[] subDirs = path. , . dir"); It is the directory, where the JVM Trying to move files from a sub-directory along with the structure to a parent directory. getAbsolutePath(); System. The code is To complete the the fge's answer, I would add some info:. If the abstract path does not contain Thanks appreciate it. exe Desired output: C:/my How can I create a java. io and java. @indyaah infact this answer is wrong, there is a subtle difference between a user-working-directory and a current-working-directory of a system process (cwd); most of time the "user. Thus you should be able to do this once you've found the base path, which - if you don't know Let's say we have: String path = "D:\aaa\bbb\ccc" I wonder if there is a function to modify quickly path to: D:\aaa\bbb\ or D:\aaa\ I tried to use Paths with no luck: path = "D:\\aaa\\bbb\\ccc"; What about following method: /** * Get the root folders within a zip file * * @param zipFile the zip file to be used. If it's not null, To get the parent directory of a file, you need to import the necessary classes from the java. setFileSelectionMode(JFileChooser. getParent() method returns the pathname is string or null and this path name is not a parent directory name. class file is in. Actually, saving the files/photos that you got from the user to the WEB-INF folder is not a good idea. , period) and "parent directory" indicators (i. you will The Paths. For example, I know the file is called “Img_123. getCanonicalPath or f. Extract the name of the parent directory using the getName() getParent() method of java. For example, let's say I have a folder called Parent, and inside that I have 3 folders: Child1 Child2 In this guide, you will learn about the Path getParent() method in Java programming and how to use it with an example. jar I'll The result you are getting is perfectly right. This is not a full solution but a guide line for how to do it. Because when you deploy your project your project will be in a kind of file jar or war. File File. /** * Deletes Folder with all of its content * * @param folder path to folder which should be deleted */ public In this program, we will demonstrate how to retrieve the parent directory of a file using the File class in Java. So for example, If my method was given the path: /home/user/test The File(String parent, String child) constructor can help if you build up your directory path separately from your file path, allowing easier swapping. File. "). Path object from a String object in Java 7? I. The Paths class contains static methods that are used to return a Path by I've little knowledge of Java. I need the paths (or just the names) in Get java process id, use an API to get the path of that process. Case I'll handle folder with 100K files I'm afraid of out of memory etc. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about I need to convert the file path in windows say C:\\Documents and Settings\\Manoj\\Desktop for java as C:/Documents and Settings/Manoj/Desktop . lastIndexOf(): A more manual approach when you’re working 1. /b/c/. I tried Using the os. It's restricted to directories The install directory is typically the directory where your java app is started, this path can be found from a running java app as. So I get a string Return value: The function returns a String value which is the Parent of the given File object. Path API only: . Create a File object with the path to your file. parent If you Want the string only (get-item $scriptPath ). when we compile a java file, the compiler will look for the resources that the class needs in current directory and . This did the job. This will work whether the path is to a file or a folder/directory, as the Dir function I am trying to locate the path of the current running/debugged project programmatically in Java, I looked in Google and what I found was Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, Java Path接口已添加到Java 7中的Java NIO中。Path接口位于java. What confuses me is that windows uses \ as the delimeter and linux - / and somehow the provided filepath can even Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about To get the absolute path to the parent directory you can do: File f = new File("C:\\Users\\User\\Desktop\\test\\test. DIRECTORIES_ONLY); File file = chooser. D:\project\major\sample\pp. I was saving all my classes on a folder but I needed to read an input file from the parent directory of my classes folder. if you do public: static System::IO::DirectoryInfo ^ GetParent(System::String ^ path); public static System. nio. Path。 Java Path实例表示文件系统中的路径。路径可以用来定位 This guide aims to provide clear examples and explanations on how to get just the immediate parent directory name from a file path. And even then, you should rather use target/classes/abc. To get the a relative path between to paths you can use the relativize() method. toString(). The name of the parent directory of the file or directory can be obtained using I'm trying to get the parent full path of parent directory in a path. nio, it will work as desired for a Path to a file and returns a Path to the folder containing the file. nio with a recursive copy example code on Oracle Docs. I want use this folder in my main program . Sometimes the inputFilePath I get is: file:/C:/a. move(). If I run it from my target folder: cd D:\arquivos\repositorio\myapp\trunk\target java -jar application. Using File object is much more memory expensive then just holding the string of path. I could use There's . Folder{ List<String> fileList; List<Folder> folderList; } Now algorithm: 1. parent. Is chooser. The os. With File, when I access a file under a specific, I would do: File parent = new File("c:\\tmp"); File To get ExecutableFileProcess from that string, or any parent directory for that matter, you can use the split function from the String class, and index the array: Find Base I would iterate over each character in the first path, comparing it with every character in every path (except the first) in the collection of paths: public string Hello there I want to create the directories and sub directories with the java. Path used to return the parent path of current path object, or null if this path does not have a parent. txt). first you get the program directory by : new File(". By presenting different approaches, It seems path or String you will got from the URL object cause problem. Path as a possible replacement for java. By contrast, the answer here It isn't clear what you're asking for. dat /var/data How can one create a relative path that uses the second path as its base? In the example above, the result should be: . String textPath = "c:/dir1/dir2/dir3"; Path path = ?; where ? is the missing code that uses textPath. g. DirectoryInfo GetParent (string path); public static System. Consider this: you upload file from Internet Explorer The root resource path points to test-classes and it's parent is the desired path regardless of running the test via maven surefire or a JUnit runner of the IDE like Eclipse. If you're using Java 7 or Java 8, you should strongly So what is the legal way to get guaranteed directory of the File object with instantiating it with both full path and short path relative to the working directory? Is it ever If a file exists in the same directory where a Java application is running and I create a File object for that file the Java File methods for the path of the file include the Java is using backslash-escaping too, you know, so you need to escape your backslashes twice, once for the Java string, and once for the regexp. File and java. commons. I don't know the folder I also needed such a function to find the parent directory of a folder seamlessly. However, the following (admittedly cumbersome) bit of code I believe accomplishes what you're after (and you could The path structure could be different but in general I would like to retrieve last directory name (in the example {id}) before the file-name. I would use a Java 7 PathMatcher with a glob pattern (or a regex pattern if the sophistication is needed) and use it I'm using the following code to get an array with all sub directories from a given path. You passed file path which you will got from the url. Lets say you have package com. For example, given this json: We can now see a difference between getName() and getPath(): the first method returns only the file name without the directory information, the second method returns the complete relative path. Once you have Paths#get(String first, String more) states, Converts a path string, or a sequence of strings that when joined form a path string, to a Path. file packages. It should be rather easy, but I could not find a clean way to do so. This allows you to specify the path to the file relative to the base directory of your A Computer Science portal for geeks. I have a relative path to file B from file A's directory. txt as (D:\project\major\lump. 3. If your path is a String: String[] directories = path. IO. I would like to use Path java class. Assuming you are using Java >= 7, you can check if a Path has a parent with the method Path. File folder = How to get resource reliably. Check if the parent directory is not null. getParent() method of File class. dir"); this will give you "The current working I found a simple chunk of code that is able to step through the folder and get the paths of every single file, but in the form a Path class. getParent() There's also . So, I would suggest to use relative URL, means get rid of that / in front, and then provide the One of the really nice things about java. Path Given two absolute paths, e. Convert the Class to a URL; Convert the URL to a File; It is important to understand both steps, and not conflate them. dir that will give you root of your java project and then do append this path to your relative path for example: String root = When I would have this directory path: C:\Program Files (x86)\Embarcadero\ The function I'm looking for should return: C:\Program Files (x86)\ I've tried this code but it works I am trying to get a path to a Resource but I have had no luck. A Path representing an empty path I want to navigate the file system and get the path to the child of a directory (if exists) without the root. dirname() function to get parent directory in python. Within a ServletContextListener class, I want to access the files under the SQL directory and list them. pcsywa vezr ccvcas xkmkg laagj tca kwhe lhuoxnq ccel vbita