How to take string input in java using scanner class

How to take string input in java using scanner class. if user entered 1 2 3, input = "1 2 3"). However, it would help if we used a delimiter to separate each input. Scanner schoolData = new Scanner(System. nextLine(); // from console input example above. It can throw NumberFormatException if input value cannot be converted to int. Or create a GUI. nextLine () and split () each line into an array. Then we created a variable called number that collects the value the user submits to the console. substring(originalString. , regions and the usePattern() method. Scanner sc01 = new Scanner(File “myFile”); 3. The first step is to initialize the scanner class by using the appropriate constructor based on the input type such as InputStream, File, or String. Scanner; import java. This is probably the most preferred method to take input. You will get the output: Read line:: e 1 Read line:: line 2 Read line:: line 3 Read line:: line 4. Mar 12, 2024 · To read multiple values, we use split(). Scanner; Next step is to create an object of the Scanner class. Scanner scan = new Scanner(System. :) – The above statement creates a constructor of the Scanner class having System. For example, if want to take input a string or multiple string, we use naxtLine () method. Using Scanner Class. (Truncate the string after giving some space from keyboard, only show string before space. in); Print the row and col number and then the entre the matix data and print it in matrix form. but in by using scanner class how it possible pls tell me. Once the import of the package is done, the next step is to create the object of the Scanner class. readLine(); 2. inM as an argument. . The first time I called . println("String: " + s); System. Java nextLine () Method. Scanner; class Main { public static void main(String[] args) { // creates an object of Scanner . toCharArray(); This reads next line and converts it to an array of chars. Jul 10, 2019 · I recommend you don’t use SimpleDateFormat and Date. array[x] = scanner. Once you're done, type in 0. Feb 13, 2011 · I have been trying all weekend to find a way to get my program to answer a question using a sting with a scanner class. Oct 5, 2015 · System. return address; public void setAddress (String schoolAddress) {. You can discard the result instead of assigning it to a: int a = in. To take a single-line string input in Java using the Scanner class, we can use the nextLine() method. Nov 29, 2023 · Let’s say our scanner receives two lines of text. NONE; private String question = ""; public Question(String questionString, Choice choice) { this. I have a method to output the highest value, lowest value, average value and I need a sort method. readLine()); for(int i=0;i<T;i++) {. Oct 21, 2012 · It also does not read the newline. in : Scanner sc = new Scanner(System. Dec 18, 2015 · Use the following input to the Scanner: line 1 line 2 line 3 line 4. The Syntax is given as: Scanner sc = new Scanner(System. println("Enter The Number Of Matrix Columns"); int col = scan. Use want = scan. It works just like taking inputs from the keyboard. println(in = (scan. nextInt();, similarly use others. //read input from the input stream. Import java. Code: Scanner chopper = new Scanner(System. use replaceAll to remove numbers 0-9 from user input. println (String). For example I need to get my program to answer a question like. ArrayList; public class Main { public static void main (String[]args) { System. nextLine(). To create a Scanner object, you can use the following constructor: Oct 4, 2020 · The next() function will only return the next token. Each of the introduced number should be separated by ENTER key. nextInt(); } public static void drawCirlce() { //Code to draw a circle of size given input into scanner. then compute the number of occurrences and print the following output: where the second number is the number of occurrences of the first number. Scanner obj1 = new Scanner (File filename); Object to read from the input stream. Note: Not The Next line (Example) My mission in life is not merely to survive, but to thrive; The code above creates a Scanner object named and uses it to read a String and an int. String s= inp. The nextLine () method moves the scanner down after returning the current line. If you’ve know Java Classes, you’ll know how to create class objects. The nextLine () method of the Scanner class is used to read the entire line entered by the user. First, we need to create a Scanner class object which wraps around the system input. nextInt(); Feb 9, 2021 · address = sc. public class User { private String First_Name; private String Last_Name; public String getFirst_Name() { return First_Name; } public void setFirst_Name(String first Jan 8, 2016 · You could simply do: String myLowerCaseInput = in. Jun 14, 2018 · Hence write an import statement at top, say import java. You can then split the values by comma: Jun 21, 2016 · 3. I think you might know the reason to this output. Nov 16, 2012 · T cases follow. readLine()); but taking input like this takes a lot of running time. The first one is a person’s name, and the second line describes the person briefly: String input = new StringBuilder (). nextLine(); so it skips the input next time . Its better to decide what type you enter before creating the object of class array. How to take space separated input in Java using BufferedReader? Please change the code accordingly, i wanted the values of a, b, n as space seperated integers and then I want to hit Enter after every test cases. My code so far: BufferedReader inp = new BufferedReader (new InputStreamReader(System. This is why people often have problems with the stringA == stringB or stringA == "expected contents of stringA", and should instead use stringA. hasNext(String pattern) only returns true if the next token matches the pattern. question = questionString; this This allows you to use the methods belonging to the Scanner Class. arr[0]="apple"; arr[1]="mango"; arr[2]="banana"; . equals(stringB); - == compares the objects, whereas equals() compares the contents. Scanner; util - package, Scanner - Class . append( "Michael Jackson\n" ) . in); Sep 3, 2008 · String input = scanner. The nextLine () method reads the text until the end of the line. Scanner sc=new Scanner(System. You should get the String using scanner. Let us discuss both the methods one by one in order to get a better understanding by implementing the same clean java programs. The reason for your problem is that following the preceding nextInt(), you're still on the same line, and nextLine() returns the rest of the current line. For example, this code allows a user to read a number from System. Jul 10, 2018 · import java. in): //receives input from the console. public static class Question { private Choice correctChoice = Choice. This is because i am regularly failing in test cases. Each case consists of two lines. A console is a device typically associated to the keyboard and display from which a program is launched. int i = Integer. address = schoolAddress; Whenever you create the PrimarySchools object with empty constructor it'll ask for the addrerss and store. After double declaration, you have to The Java Scanner class breaks the input into tokens using a delimiter which is whitespace by default. EXAMPLE. split(" "), to split around the spaces. If there is nothing on the line, it simply consumes the newline and moves to the starting of the next line. nextInt(); In this example, we created a variable called input that collects the next value the user inputs into the console. nextInt(); //defining 2D array to hold matrix data. If need be, pass that Scanner into this method using a parameter. There are a few ways to take string array input in Java. I'm writing a program to take a sequence of integers from console, e. The resulting tokens may then be converted into values of different types using the various next methods. Scanner scan = new Scanner (System. in parameter is used to take input from the standard input. If input is equals to exit then program is going to exit. time, the modern Java date and time API. Apr 12, 2017 · Stack Overflow Public questions & answers; Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Talent Build your employer brand Apr 20, 2012 · It is, however, possible to use Java's regex classes for a limited form of lexical analysis. That is because after reading int there left a new line character which was consumed by your scan. and any help full "for each" in java String arrays Mar 8, 2021 · 3) Scanner Object Creation in Java and Their Usage. So when you continue reading with scan. Using Space as Delimiter. parseInt(inp. It is the simplest way to get input in Java. Scanner. Second, this is what you need inside your loop: matrix[i] = stdin. Currently I'm using the Scanner class to get the input, but the loop I'm using to check each line does not break. nextLine(); next, it reads everything till the next line separator. Say Scanner in = new Scanner(System. int n = Integer. Say to read integer from user use in. If you change the pattern to "[A-Za-z]+", then you'd get three tokens, which may be what you intended. parseInt(br. String line = in. Here's an example of a rudimentary scanner built on top of Java's regex classes. it cannot read anything after it gets the first space. The next () method returns the next token/ word in the input as a string and chatAt () method returns the first character in that string. answered Feb 25, 2014 at 4:42. After that using the object we call the nextLine () method to take String input. Who is on the 5 dollar bill? Input would be Lincoln and other inputs would be invalid the question will have 3 choices so the logic has to work. Oct 6, 2021 · Creating a Scanner Class Object. Therefore don't create 2 Scanners to take input from same Stream. BufferedReader br=new BufferedReader(new InputStreamReader(System. So you input 3 and press "Enter", the end of line is read by in. in); Finally we take input using the following command. print("Enter numbers: "); // This inputs the numbers and stores as one whole string value // (e. 5. in); int a=sc. If your String is named "cheese" and your scanner is named "in", here's what this looks like: cheese = ""; // empty 'cheese' of prior input. Also, we need to merge this array with the final result array. We use the next () and charAt () method in the following way to read a character. in as the argument for the Scanner’s constructor. Our code will print: myString is: Hi. in); int number = input. nextLine(); System. char c = (char) System. So, if your input has three words separated by a space, it will only return one word at a time. nextLine() instead of scanner. Feb 3, 2017 · I am supposed to use the Scanner in Java to receive a 14 char input and have all the letter char output in uppercase format. I would like to know the faster way to take Dec 14, 2023 · To read multiple inputs on the same line, we can use the Scanner class along with the next () or nextLine () method. It then closes the Scanner object because there is no more input to read, and prints to stdout using System. Second answer above is the most simple one. parseInt(System. A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace. Jul 13, 2012 · 4. where NY represents the prov variable and the "15" represents the tax variable. int[] array = new int[5]; for(int x=0; x<array. printStackTrace(); Which will read the first byte in the first available line and cast it to a char. Nov 4, 2015 · In Java i take Input using standard Scanner and BufferedReader Classes like: Scanner sc=new Scanner(System. We import the Scanner class from the java. util package. in)); int T= Integer. Dec 28, 2023 · How to take string array input in Java. This article has demonstrated efficient methods to capture multiple inputs using the Scanner class, including the use of nextLine(), nextInt(), and nextDouble() methods. It would be also wise to check that the length of the original string is more that the amount you substract (4 in the example above). nextInt(); scan. parseInt( input ); // converts a String into an int value The Integer class contains conversion methods for changing String data into int values and vice versa. read(); e. I am trying write code which can recognize if the user presses the enter key in a console based program. Using nextInt ( ) method of Scanner class. We have then used the nextLine() method of the Scanner class to read a line of text from the user. The Scanner class can be used to read input from a variety of sources, including the keyboard, files, and network connections. equals("exit")); sc. Aug 29, 2018 · C:\CODE>java Compare Enter a NAME: Henry Invalid Input It doesn’t accept the String value “Henry” thats why the else statement keeps displaying “Invalid Input”. It can read input from a File, InputStream, and a String respectively. When you use Scanner. Let's take an example. Jun 19, 2023 · 1. readLine()); // for Integer Input. BufferedReader br = new BufferedReader(new InputStreamReader(System. There are a few different ways to take input in Java. println("enter an integer"); int myint = keyboard. To take input of an array, we must ask the user about the length of the array. The method returns the line that was skipped. So you need to handle it accordingly. The Scanner class can be used to read input from a variety of sources, including the console, files, and sockets. i could read the String into array like that below. nextLine(); //read in a line of input. Those classes are poorly designed and long outdated, the former in particular notoriously troublesome. next(); instead of nextLine(). println("Introduce the sequence of numbers to store in array. nextInt(); the scanner reads the number from the input, but leaves the line separator there. The second step is to wait for the input token using hasNext () method. Apr 25, 2017 · Scanner's buffer full when we take a input string through scan. Instead use LocalDate and DateTimeFormatter, both from java. length; x++) //Prompt as many times as the array size. Optionally set a delimiter other than the enter key. You create a new String object which is made up from the previous two String objects. println("Choose a size!"); int size = input. I have been told that this can be done using either Scanner or, buffered input reader. You'll get an array, and if the first character is blank, the first String in the array will be an empty string: Apr 12, 2016 · Need Java array help using scanner class to output an average and sort method (4 answers) Closed 8 years ago . Jul 23, 2022 · To take String input from the user with Java’s Scanner class, just follow these steps. The Scanner class of the java. A complete token is preceded and followed by input that matches the delimiter pattern. Import first : import java. Scanner class. NONE; private Choice userChoice = Choice. Is there an easy way to input numbers without typing input scanner for each package. toString(); Scanner sc = new Scanner (input); For simplicity, we’ll feed Scanner objects with Apr 20, 2013 · 5. Here is an example: BufferedReader br = new BufferedReader(new InputStreamReader(System. In the main method, we create a Scanner object named scanner to read input from the console. Create a question class which will have question and correct answer, user entered answer. Current Code package getxml; Nov 21, 2019 · From the documentation of Scanner. Scanner sc = new Scanner (System. in); To read a character in Java, we use next () method followed by charAt (0). append( "He was the 'King of Pop'. And i have to take a string input of 6-7 words minimum. Jul 23, 2014 · So the second option, the second to last line, what exactly is happening? isn't the object being created "n" and not the "nameValue"? The reason I ask is because I am attempting to make a lending library, so that a person puts in a new media (ex Halo 3) I would want them to input Halo 3 then have that save as a new object so I can change its format and whether who it was loaned to with other Aug 3, 2022 · Steps to Initialize and Use Scanner. next() for Scanner sc = new Scanner(System. next(); Apr 16, 2011 · The key is to accept input as type String and use the . If you want the last part of the string, it is safer to use something like: originalString. If needed, set the delimiter and character set to use. Here is How to take input in Java. The second line contains two integers M, P separated by a space. Tip: use scanner. So, you can read using readLine and convert it to int using Integer. nextLine method to read in names. nextline(). May 31, 2019 · The problem is with the scan. in); //for a int. toCharArray(); Thanks Oct 14, 2015 · I am working on a Java program that reads a text file line-by-line, each with a number, takes each number throws it into an array, then tries and use insertion sort to sort the array. So, if our input is: Hi 5. Following that, we use a for loop to accept user input and save it in an array. parseInt. . Input Example: NY 15. in); The nextLine () method of Scanner class is used to take a string from the user. Java does not provide any direct way to take array input. cheese = in. It also converts the Bytes (from the input stream) into characters using the platform's default charset. 2. You need to use nextLine() method instead, in order to get the full input sentence. 4. in); char c = reader. in); String input = ""; do{ input = sc. Here’s an example: Jul 9, 2013 · You can use Scanner class. nextLine() reads the whole line. //read input from a file (“myFile”) 2. Dec 28, 2023 · 1. Feb 5, 2021 · Conclusion. It is defined in java. To take a single-line string input in Java using the BufferedReader class, we can use the readLine() method. util package should be import while using Scanner class. Aug 8, 2022 · To perform user input with the Scanner class, follow these steps: Create an instance of the Scanner with the new keyword. Use the Integer class to parse the string of characters into an integer. import java. A byte won't cover every possible character. Scanner; Then you use like this. println("Int: " + i); } Because the Scanner object will read the rest of the line where its previous read left off. Jan 13, 2020 · The code I have written takes as input just a single string and not a whole sentence and I want a whole sentence to be taken as input: import java. nextInt(); System. Specify the System. 3. You need to consume it before reading a String. out. ) 1. and soon. The code seems to still take in the values at different lines. Jun 24, 2013 · There are two ways to do that: Which will read the first available line, and extract the first character, or. java Nov 7, 2017 · java. println("Double: " + d); System. Maybe even stick with the Scanner Class, it works fairly decent. charAt(0) method on the returned String. The documentation is clear in that " [the] scanner does not advance past any input". It means it is going to read from the standard input stream of the program. in); or (visible to the current class - any other static method (main() in your case) ) private static Scanner input = new Scanner(System. Example 1: Read a Line of Text Using Scanner. nextInt() only receive a int number, doesn't receive a new line. nextLine(); //receives everything they type until they hit enter. Aug 20, 2012 · Try using String. Use Scanner class methods as per your data type to read input from user. May 15, 2011 · 18. Next, let’s see how it works: String[] result = new String [] {}; Scanner scanner = new Scanner (input); while (scanner. Mastering multiple string input in Java using a scanner is a fundamental skill for Java developers, enhancing the versatility and interactivity of Java applications. Use the Scanner’s next () or nextLine() methods to convert user input into the appropriate type. ENGLISH); " but it tells me str cannot be resolved and that the locale can't be resolved. readLine(); //for string input. in); First, you need to add stdin. In fact, the addition of the Scanner class made it much easier, because of the new Matcher API that was added to support it, i. util. nextInt(); in. *; to make Java’s Scanner class available; Use the new keyword to create an instance of the Scanner class; Pass the static System. In your case, "asda" is the next token, and that does NOT match "[A-Z]+". in); System. The java. toUpperCase(Locale. That means, if you call input. Here's an example: String in; Scanner scan = new Scanner("4r1e235153a6d 6321414t435hi4s 4524str43i5n5g"); System. Scanner input = new Scanner(System. So solution is that we can create a new object of Scanner , the name of the object can be same as previous object. Still not sure why but using a new instance of scanner has solved the problem. nextInt(); or. nextLine and it did not wait for your next input. println("Enter a list of number: "); int[] numCount = new int[10]; Jul 29, 2013 · Here is my User. For some reason it doesn' May 2, 2010 · 6. One way to read multiple inputs on the same line is to use a space as a delimiter. nextInt() method - it only reads the int value. Dec 19, 2012 · There is no API method to get a character from the Scanner. in)); String str = br. "); Jan 7, 2016 · Wow that looks like bad design - if you ask for an integer an d do a nextInteger() the scanner will give you the integer, but it is now holding a new line character in its buffer as the user has to press enter to submit the integer, so if you later want to prompt the user for a string it will not wait for input and just give you back a new line character. in); Here, we have created an object of Scanner named input. Jul 13, 2010 · 19. nextLine(); Jan 13, 2018 · Algebraic? Anywaysyou could use BufferedReader Class and wrap it with the InputStreamReader Class or even the Console Class if you using the Java SE6 or higher (see this SO Post). next() reads the string before the space. Feb 1, 2023 · There are 2 methods to take input from the user which are separated by space which are as follows: Using BufferedReader Class and then splitting and parsing each value. Create an object of Scanner class. in); String str = sc. java class. replaceAll("[0-9]", ""))); // use . If your string is not delimited: *edited* That second example can be easily implemented by just calling String#toCharArray(), which returns a copy of the characters in the string. Scanner; // imports class so we can use Scanner object public class Test { public static void main( String[] args ) { Scanner keyboard = new Scanner( System. hasNextLine()) {. It is only a way to take multiple string input in Java using the nextLine () method of the Scanner class. next() does not read white spaces from the keyboard. in); to (visible to all other classes - you said global) public static Scanner input = new Scanner(System. That would take in all the information they enter. I need help w Apr 2, 2013 · String shape = input. We use System. println("enter string for c"); String c=sc. nextLine(); Sep 14, 2015 · however if my array had 1000 numbers, this process would have become tiresome. next(). Alternatively, you can use the BufferedReader class. close(); In order to exit program, you simply need to assign a string header e. Yes, by using loops. int number = Integer. The main purpose of the Scanner class is to parse primitive types and strings using regular expressions; however, it is also can be used to read input from the user in the command line. How can I do this using java. Thus, you need to follow it with a Scanner. Here's a smallest snippet to reproduce the behavior: Scanner sc = new Scanner(System. – May 23, 2019 · The scanner object was used earlier in the code to first read some ints. Steps to create the Scanner objects are as follow: Object to read from file. console(). util package is used to read input data from different sources like input streams, files, etc. e. – Obicere. After importing the package, the following lines of codes can be used to create an object of the Scanner class. int first_value = scan. Aug 17, 2013 · I am programming using Java. readLine(); Oct 8, 2014 · If you call input. Finally, we use another for loop to print the array’s elements. Use a for-loop or a while loop. \n" ) . Oct 4, 2017 · In this program I meant to write that : it should get only positive numbers from user via scanner and if they are positive - it need to add them to the 'list' Array list. The System. After reading the line, it throws the cursor to the next line. And i have checked many sites they all said it is not possible. Scanner sc = new Scanner(System. Scanner reader = new Scanner(System. Scanner keyboard = new Scanner(System. } public static void drawSquare() { //Code to draw a square of size given input into scanner. in)) //string str = br. print to prompt the user to enter a string. Once the input is read, nextLine () positions the cursor in the next line. Jan 5, 2024 · A quick and practical set of examples for using the core Scanner Class in Java - to work with Strings, Files and user input. isEmpty() method to check whether the user entered anything or not. Sep 6, 2014 · 3. Method 1: Jan 27, 2018 · Taking input from user is only using Scanner class in java. If their input is: "Jaime Smiths, abcd5432, Sydney, how's going". nextDouble() method does not consume the last newline character of your input, and thus that newline is consumed in the next call to scan. Oct 13, 2012 · What you need is more than char to handle your requirement. in);. in object to the Scanner’s Java constructor; Use Scanner’s next() method to take input one String at a time Nov 17, 2014 · Because in this case, it's not the same String object. nextLine(); Sep 25, 2021 · I want the input to take in both the prov and tax on the same line despite them being different data types. You can try the below code: -. println("Enter The Number Of Matrix Rows"); int row = scan. nextLine it was coming back as an empty string. Read until the end of the line or "/n". String string = "STRING"; char[] chars = string. next() because scanner. Some characters of the first line are in the Scanner s1. And after deciding the types, create the object using eg : array<Integer,String> arr = new array<Integer,String>. Nov 18, 2020 · Here is the syntax for the Java Scanner class: Scanner input = new Scanner (System. With the scanner it would be advisable to read a short. myInt is: 5. in)); int a=Integer. in); Jul 1, 2021 · I need to get multiple line Input from a User in Java. Scanner; public class Solution { public receiving input using Scanner class (I got this) taking input from scanner and making it a String. 1. Jul 15, 2017 · How to read and use the String array using scanner class or other in java . nextLine(); public String getAddress () {. nextLine () reads input including space between the words (that is, it reads till the end of line \n). enter image description here This because in. nextLine() you receive the "\n" Enter key. in); Feb 9, 2018 · It's because the scan. But we can take array input by using the method of the Scanner class. exit. nextInt(); Side note : If you are using nextInt() with nextLine() you probably could have some trouble cause nextInt() does not read the last newline Also, next () places the cursor in the same line after reading the input. next() and invoke String. The Java Scanner class is widely used to parse text for strings and primitive types using a regular expression. It reads String input including the space Sep 15, 2016 · I need to read spaces (present before string and after String) given as input using Scanner Note : if there is no spaces given in input it should not add space in Nov 29, 2023 · To solve the problem, we can read each input line using Scanner. in ); System. Then we make an array arr with the size ‘arr_size’. in. Later I tried to use the same scanner . length()-4); Replace 4 with the actual character count you want to output. readLine()); The question is "How to read from standard input". Which means first i'll input the number of test cases then i'll press the Enter key. Feb 16, 2024 · In this example, we first utilize the Scanner class to accept user input and save the array size in the size variable. nextLine(); after reading n to skip the new line character. charAt(0); Just to be safe with whitespaces you could also first call trim() on the string to remove any whitespaces. Or for having a generic type, use Object. toLowerCase(); Edit: as a side note, I highly doubt that you will want to create the Scanner object in this method, since you should only create one Scanner object based on System. next() method finds and returns the next complete token from this scanner. 1. It provides many methods to read and parse various primitive values. this. nextInt(), it does not consume the new line (or other delimiter) itself so the next token returned will typically be an empty string. I've tried entering some of the code I found through Google such as " str. println(input); } while(!input. After that, we use a Java for loop to take the input from the user and the same for loop is also used for retrieving the elements from the Aug 25, 2013 · Scanner in = new Scanner(System. To use the Scanner class to read a string array, you can use the following steps: 1. next():. g. The most common way is to use the Scanner class. probably you can get it from user. I do not understand(or know how to use) buffered input reader. You can do it simply by the following steps: Use the BufferedReader Class and wrap it with the InputStreamReader Class. op cw vi vd hz bt ju ge yd tq